Question

Mason is preparing for an endurance running competition. On Friday, he ran 15 3/5 miles. On Saturday, he ran twice as much as he did on Friday. On Sunday, he ran 3 3/4 less than he did on Saturday. How many miles did Mason run for three days?

Answer 1

He ran for 34 and 19/20 miles

Answer 2

Answer:

$74 \frac{5}{20}$

Step-by-step explanation:

On Friday, he ran $15\frac{3}{5}$  miles.

converting mix number to fraction we get,

$15\frac{3}{5}$ =$\frac{75+3}{5}$ =$\frac{78}{5}$

On Saturday, he ran twice as much as he did on Friday.

so, for Saturday it is,

2 x  $\frac{78}{5}$  miles

=$\frac{78 x 2}{5}$

=$\frac{156}{5}$

On Sunday he ran $3\frac{3}{4}$ less than Saturday.

$3\frac{3}{4}$=$\frac{12+3}{4}$ =$\frac{15}{4}$

So, for Sunday it is-

$\frac{156}{5}$ - $\frac{15}{4}$

=$\frac{156x4-15x5}{20}$

=$\frac{624-75}{20}$

=$\frac{549}{20}$

So, for three days,

total distance would be-

$\frac{78}{5}$ + $\frac{156}{5}$ + $\frac{549}{20}$

=$\frac{78x4 + 156x4 + 549}{20}$

=$\frac{312+624+549}{20}$

=$\frac{1485}{20}$

=$74 \frac{5}{20}$

So, Mason ran  $74 \frac{5}{20}$  miles in three days.