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2 years ago

B. During two years of college, a student earned $12,000. The second year she earned $500

Mathematics

1 answer:

Nana76 [90]2 years ago

5 0

Answer:

6000 dollars duhhhhhhhhhhhh

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How to factor -2 out of -6x+10

KIM [24]

Just divide -6x+10 by -2 and take out what's common.

-6x divided by -2 would be 3x.
10 divided by -2 would be -5.

So the answer is -2(3x-5).

$\sf\ Answer: -2(3x-5)$

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3 years ago

What is 16,473 to the nearest hundred

Verizon [17]

The number "4" is in the hundreds place. To the right is 7, and since it's greater than five it rounds up. So 16,473 to the nearest hundred is 16,500. Hope this helped!

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3 years ago

What is the area of the white boarder? 2cm 8cm 9cm 15cm

antiseptic1488 [7]

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3 years ago

Read 2 more answers

Please answer, Thank you. Image below.

Bezzdna [24]

Answer:

88°

Step-by-step explanation:

The triangle is an isosceles triangle, so two of the angles are both 46°. We also know that the sum of all the angles in any triangle is 180°, so we can set up the following equation:

46° + 46° + e = 180°

Solving this gets e = 88°.

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2 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

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2 years ago