Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
You normally use division what u do is u did if 24.99 by 2
Answer:
63m^11 no^12
Step-by-step explanation:
Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation
(7nm^5 o^2) × (-3m^3 o^5)^2
7m^5 no^2) ×(-3m^3 o^5) ^2
(7m^5 no^2) × (3m^3 o^5)^2
7m^5 no^2 × (3m^3 o^5) ^2
7m^5 no^2 × 9m^6 o^10
63m^11 no^12
Answer:
here
Step-by-step explanation:
8/1 or 8
I dont really know the answer but u can use this app called photomath and it will help
