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3 years ago

What is the standard deviation of a sampling distribution called?

Mathematics

1 answer:

GarryVolchara [31]3 years ago

8 0

Answer: Standard error.

Step-by-step explanation:

If the population is normally distributed , then the standard deviation of a sampling distribution of the sample mean $[tex]\overline{x}$ [/tex] is known as standard error which depends on population standard deviation $(\sigma)$ and the sample size (n).

$\sigma_x=\dfrac{\sigma}{\sqrt{n}}$

It measure the variability in the sample statistics that happens by chance.

Thus, the standard deviation of a sampling distribution is called the <u>standard error</u>.

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Is a 90° angle perpendicular

Dima020 [189]

Answer:

yes

Step-by-step explanation:

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3 years ago

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Find the perimeter in feet and in yards

Goryan [66]

<h3>Given</h3>

a circle with diameter 8 yd

the circumference in feet and yards

<h3>Solution</h3>

The circumference of a circle is given by ...

C = πd

where C is the circumference and d is the diameter. For your circle, the circumference is

... C = π(8 yd) = 8π yd ≈ 25.13 yd

There are 3 feet in a yard, so 3 times as many feet.

... C = 24π ft ≈ 75.40 ft

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4 years ago

samantha is making punch for a class picnic. there are 25 students in her class. Samantha uses 1 gallon 2 quarts of orange juice

Alex_Xolod [135]

Answer:

4 gallons
yes

Step-by-step explanation:

A quart is 1/4 gallon, so the total of liquid ingredients for the punch is ...

(1 2/4 gal) +(3/4 gal) +(1 3/4 gal) = 2 8/4 gal = 4 gal

Samantha made 4 gallons of punch.

1 cup is 1/16 gallon, so 2 cups each for 25 students requires ...

(1/16 gal)(2)(25) = 50/16 gal = 3 1/8 gal

Samantha made more punch than that, so there will be enough for 2 1-cup servings for each student.

6 0

3 years ago

If 2^a =0.5 and 5^b=125, what is the value of a^b +b^a?

kifflom [539]

9514 1404 393

Answer:

-2/3

Step-by-step explanation:

2^a = 0.5 = 2^-1 ⇒ a = -1

5^b = 125 = 5^3 ⇒ b = 3

Then the expression a^b +b^a is ...

a^b +b^a = (-1)^3 +3^(-1) = -1 +1/3 = -2/3

3 0

3 years ago

Last season two running backs on the Steelers football team rushed or a combined total of

belka [17]

Answer:

310 yards and 1,240 yards

Step-by-step explanation:

Let first football player rushed x yards.

One football player rushed 4 times as many yards as the other, then the second player rushed 4x yars.

In total, they rushed

$x+4x=5x$ yards.

Last season two running backs on the Steelers football team rushed or a combined total of 1,550 yards.

Hence,

$5x=1,550\\ \\x=\dfrac{1,550}{5}=310\ yards\\ \\4x=310\cdot 4=1,240\ yards$

8 0

4 years ago