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Stels [109]
3 years ago
13

Simplify 6+5m/3=m-2

Mathematics
2 answers:
BigorU [14]3 years ago
6 0

Answer:

m=-12

Step-by-step explanation:

Given equation is \[6+\frac{5m}{3}=m-2\]


Simplifying the equation:

\[6+\frac{5m}{3}-m+2=0\]


\[=>8+\frac{5m}{3}-m=0\]


\[=>8+\frac{5m-3m}{3}=0\]


\[=>8+\frac{2m}{3}=0\]


\[=>\frac{2m}{3}=-8\]


\[=>m=-8*\frac{3}{2}\]


\[=>m=-12\]


The given equation can be expressed as m=-12.

nikitadnepr [17]3 years ago
4 0

Answer:

m = -12

Step-by-step explanation:

Subtract 6 from both sides

6 + 5m -6 = m - 2 - 6

Simplify

5m/3 = m-8

Multiply both sides by 3

5m * 3 = m * 3 - 8 * 3

Simplify

5m = 3m - 24

Subtract 3m from both sides

5m - 3m = 3m - 24 - 3m

Simplify

2m =  - 24

Divide both sides by 2

2m/2 = -24/2

Simplify

m = - 12

         

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The stemplot displays the selling prices of homes for ABC Realty in April.
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The stemplot displays the entire values for the selling prices of homes for ABC Reality in April.

The correct set of data for the stemplot is the option;

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<h3>Method by which the above option is selected</h3>

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459,000, 482,000, 213,000, 225,000, 276,000, 277,000, 287,000, 123,000, 181,000, 181,000, 196,000, 67,000, 85,000, 92,000

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2 years ago
It is 18°C at 8 am, and 14°C by noon. The change in temperature from 8 am to noon is
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Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

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Check the picture below.

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