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irina1246 [14]
3 years ago
14

Ann works at a store in the mall and earns a wage of $8 an hour. She earns $10 an hour if she works on the weekends. Last week s

he worked 24 hours during the week and 16 hours on the week
Mathematics
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

Ann makes $252 this week

Step-by-step explanation:

To find the amount she made in total, mutliply the rates by the amount of hours she worked at that rate. Start with the weekday rate.

$8 * 24 = $192

Now do the weekend rate

$10 * 16 = $160

Now add the two amounts together

$192 + $160 = $252

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I'm really bad at these questions
Diano4ka-milaya [45]

Answer:

30 centimeters^2

Step-by-step explanation:

The area of a triangle can be found using the following formula.

A= (b*h)/2

In this triangle, the base is 12 cm. The height is 5 cm, since it forms a right angle with the base.

b= 12 cm

h= 5 cm

A= (12 cm * 5 cm) / 2

Solve inside the parentheses first. Multiply 12 cm and 5 cm.

A= (60 cm^2) / 2

Divide 60 cm^2 by 2

A= 30 cm ^2

The area of the triangle is 30 square centimeters.

6 0
3 years ago
Read 2 more answers
At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

8 0
3 years ago
A customer purchased a total of 23 hamburgers and chicken sandwiches. Each hamburger costs $3.50 and each chicken sandwich costs
Bezzdna [24]

Answer:

25 2/7

Step-by-step explanation:

88.50/3.50 divide 88.50 by 3:50

6 0
3 years ago
Help pls
lana [24]
You can either do;


1. 90(2) = 100(2)

180 = 200


In 3 minutes, they can write 200 words. So now we can divide by 3.

3/3 = 1 minute

200/3 ≈ 66.666


or


2. 90/3 = 30 secs

100/3 ≈ 33.333


30(2) = 1 minute

33.333(2) ≈ 66.666


Either way, the admin assistant can write 67 words per minute. (Rounded to the nearest whole)
3 0
3 years ago
I need help plsssssss​
Svetllana [295]

4)Area :32cm

5)18cm

6) 49cm

4 0
3 years ago
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