I NEED ALGEBRA HELP!!!

If f(x) = 1/3x+13, then f^-1(x) =??

Sergeeva-Olga [200]

Step-by-step explanation:

Given

f(x) = 1/3x + 13

f^-1(x) = ?

Now

Let y = f(x)

or y = 1/3x + 13

Interchanging the role of x and y

x = 1/3y + 13

x - 13 = 1/3y

y = x - 13

3

Therefore f^-1(x) = x - 13

3

Hope it will help you.

7 0

3 years ago

A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe

e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= $^{31}P_5$

$=\dfrac{31!}{(31-5)!}$

$=\dfrac{31!}{(26)!}$

$=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}$

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= $^9P_2\times ^{22}P_3$

$= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}$

$= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}$

$= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}$

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

$= \dfrac{^{22}P_5 }{^{31}P_5}$

$= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }$

$= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}$

$= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}$

= 0.1549

≅ 0.155

4 0

3 years ago

A European bond has a par value of 1000 Euros, a coupon rate of 4.5 percent and a yield to maturity of 3.2 percent. The bond has

Katyanochek1 [597]

Answer:

Bond Price= 1,182.96

Step-by-step explanation:

Giving the following information:

Par value= 1,000

Cuopon= 1,000*0.045= 45

YTM= 3.2%

Number of years (n)= 10

To calculate the price of the bond, we need to use the following formula:

Bond Price= cupon*{[1 - (1+i)^-n] / i} + [face value/(1+i)^n]

Bond Price= 45*{[1 - (1.032^-19)] / 0.032} + [1,000 / (1.032^19)]

Bond Price= 633.31 + 549.65

Bond Price= 1,182.96

3 0

3 years ago

What temperature in Kalvin is 67°F? (round to 3 decimal points only)

hammer [34]

Answer:

262.594 Kelvin

Step-by-step explanation:

couldn't you just search this?

6 0

3 years ago

If F(x) = x - 1 and G(x) = 5x + 2, then find (FºG)(2) *

tiny-mole [99]

Answer:

11

Step-by-step explanation:

First, fund the value of G(2),

$g(2) = 5(2) + 2 = 12$

Plug 12 in for f(x).

$f(12) = 12 - 1 = 11$

7 0

3 years ago