If f(x) = 1/3x+13, then f^-1(x) =??
1 answer:
Step-by-step explanation:
Given
f(x) = 1/3x + 13
f^-1(x) = ?
Now
Let y = f(x)
or y = 1/3x + 13
Interchanging the role of x and y
x = 1/3y + 13
x - 13 = 1/3y
y = <u>x </u><u>-</u><u> </u><u>1</u><u>3</u>
3
Therefore f^-1(x) = <u>x </u><u>-</u><u> </u><u>1</u><u>3</u><u> </u>
3
Hope it will help you.
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