<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
Answer:
8 cups is greater then 8 oz
Step-by-step explanation:
13-11 9/20 = 1 11/20 sooo G
I believe the correct answer from the choices listed above is option A. Given a segment with endpoints A and B and the steps given above, the figure that you can construct would be a perpendicular bisector. <span>The </span>perpendicular bisector<span> of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.</span>
