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frosja888 [35]
3 years ago
15

Evaluate: 30 - 12÷3×2 =

Mathematics
1 answer:
lara [203]3 years ago
7 0

Answer:

22

Step-by-step explanation:

We can use the order of operations (PEMDAS), to solve this equation.

We must first multiply and divide, and order. This means we divide 12 by 3 and get 4, then multiply that by 2 and get 8. (30-12÷3×2,30-4×2,30-8). Now we just subtract 8 from 30 and get 22 as our answer.

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Answer:

89⁷/₈ in

Step-by-step explanation:

The perimeter of a shape can be found by adding up the side lengths.

So, we have to find 20⁹/₁₆ + 23³/₈ + 21⁵/₁₆ + 24⁵/₈

Common denominator (16): 20⁹/₁₆ + 23⁶/₁₆ + 21⁵/₁₆ + 24¹⁰/₁₆

Add fractions: ⁹/₁₆ + ⁶/₁₆ + ⁵/₁₆ + ¹⁰/₁₆ = ³⁰/₁₆

Simplify: ³⁰/₁₆ = ¹⁵/₈ = 1⁷/₈

Add whole numbers: 1⁷/₈ + 20 + 23 + 21 + 24 = 89⁷/₈ in

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The solution to the equation is x = 0, 2

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Ramón and Merissa are driving to New York City after college. The first 300 miles they spend $12.50 on gas.
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Answer:

Step-by-step explanation:

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Simplify: StartRoot StartFraction 576 Over 64 EndFraction EndRoot The prime factorization of 576 is. The prime factorization of
riadik2000 [5.3K]

The prime factor of the 576 is 2^6 * 3^2 and the prime factor of the 64 is 2^6. And the expression \sqrt{\dfrac{576}{64}} is equal to 3.

<h3>What is simplification?</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

The expression is \sqrt{\dfrac{576}{64}}

The prime factor of the 576 will be

576 = 2^6 * 3^2

The prime factor of the 64 will be

64 = 2^6

Then the expression will be

\sqrt{\dfrac{576}{64}} = \sqrt{\dfrac{2^6 * 3^2}{2^6}}\\\\\sqrt{\dfrac{576}{64}} = \sqrt{3^2}\\\\\sqrt{\dfrac{576}{64}} = 3

More about the simplification link is given below.

brainly.com/question/12616840

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2 years ago
Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12
melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

The probability that a passenger does not show up is 0.10:

This means that the probability of showing up is 1-0.1 = 0.9. So p = 0.9

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets

This means that n = 125

Using the approximation:

\mu = E(X) = np = 125*0.9 = 112.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.9*0.1} = 3.354

(a) What is the probability that every passenger who shows up can take the flight

This is P(X \leq 120), so this is the pvalue of Z when X = 120.

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 112.5}{3.354}

Z = 2.24

Z = 2.24 has a pvalue of 0.9875

98.75% probability that every passenger who shows up can take the flight

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