Answer:
The client
Explanation:
On a client/server network, THE CLIENT computer initiates the process of assigning an IP address through DHCP. This is because "The Client" computer will serve as the Domain controller in which other computers of the network can find. Hence, The Client computer initiates the process of assigning IP addresses through DHCP to achieve this.
Though, in some case. A user can manually assign the IP address to computer if it is not through DHCP
If the website is talking about someone or something close to the heart of the website. You wouldn't want the website you work for to talk trash about you.
Answer:
The three Linux distributions are Arch Linux, Ubuntu and Fedora. In order to get more detailed information go to the wikipedia page of comparision of linux distributions.
Strengths and Features of these three are attached.
The two linux newsgroups are
1) Comp.os.linux.announce
2)comp.os.linux.networking
Explanation:
Answer:
These are for the WiFi. On a few cards, the Bluetooth facility is being provided through the second antenna, and that is 2.4 GHz, and hence both the antennas are the same in length. And the 5 GHz comes with the wavelength which is half of that of 2.4 GHz, and this is you can use both the antennas for any out of the two frequencies and you can connect to only one Wi-Fi network at one time, however, it needs the second antenna to communicate with any device which is of type Bluetooth, and two at a time.
Explanation:
The answer is self explanatory.
Answer:
#include<iostream>
#include<cstring>
#include <algorithm>
using namespace std;
class Student{
public:
string name;
int rollNo;
Student(){
}
Student(string n, int r){
name = n;
rollNo = r;
}
};
class ClassRoom{
public:
Student stud[10];
int count;
ClassRoom(){
count = 0;
}
void addStudent(string str,int roll){
Student s(str,roll);
stud[count++] = s;
}
Student * getAllStudents(){
return stud;
}
};
int main()
{
string name;
char temp[20];
int rollNo, N, i;
Student * students;
ClassRoom classRoom;
i=0;
while(getline(cin, name) && cin.getline(temp,20)&&i<10){
rollNo = atoi(temp);
classRoom.addStudent(name, rollNo);
i++;
}
N = i;
students = classRoom.getAllStudents();
for(int i=0 ; i < N; i++){
cout << (students+i)->rollNo << " - " << (students+i)->name;
if(i<N-1)
cout<<endl;
}
return 0;
}
Explanation:
- In the addStudent method, increment the counter and as the value of variable s to the the stud array.
- In the getAllStudents method, return all the students.
- Finally in the main method, display the name and roll no. of students.
