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Novosadov [1.4K]
3 years ago
11

Consider the following equilibrium: 2SO2(g) + O2(g) 2SO3(g) Which of the following is a correct equilibrium expression?

Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0
The correct equilibrium expression would be one that has products over reactants, and to the power of their stoichiometric coefficient. Also, it would not include any liquids or solids.

The equilibrium expression for your balanced reaction is:
\Large K_c = \sf{\frac{[SO_3]^2_{equil}}{[SO_2]^2_{equil}[O_2]^2_{equil}}
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55 points plz help
AnnZ [28]

Answer: A FILTERING

Explanation:

WHEN YOU FILTER YOU SEPARATE (sorry for caps) btw can you check out my recent question plz

4 0
3 years ago
An element's ability to react with acid is an example of a
Dmitry [639]

Answer:

it's chemical property

Explanation:

i took quiz

4 0
3 years ago
A mixture 21.7 g NaCl 3.74 g kcl and 9.76 g licl how many moles of nacl are in this mixture
slava [35]
Moles (mol) = mass (g) / molar mass (g/mol)

Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol

Hence moles of NaCl in the mixture is 0.372 mol.

Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.

mole % = (moles of desired substance / Total moles of the mixture) x 100%

Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

Total moles of mixture = moles of NaCl + KCl + LiCl

Mass of KCl = 3.74 g 
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g  / 74.6 g/mol = 0.050 mol

Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol

Total moles =  0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
                           = (0.372 mol / 0.652 mol) x 100%
                           = 57.06% 

Hence, mixture has 57.06% of NaCl as the mole percentage.
8 0
3 years ago
The relationship between pressure and volume, when moles and temperature of a gas are held constant, is: PV = k. We could say th
pochemuha
You can say that if the volume of the gas is halved, the pressure is doubled.

The expression shows that pressure and volume are inversely proportional if temperature and amount of gas is held constant.  This means that if volume goes down the pressure needs to go up.  That also means that in order to maintain the K value, if pressure is doubled the volume needs to be halved and if the pressure is halved the volume needs to be doubled.

This relationship only works if we assume everything else (Temperature and moles of gas) to be constant.
7 0
4 years ago
1. What do gram-formula mass and atomic mass have in common? How are they different?
elixir [45]
Because they do not have the same qualities therefore they are different
3 0
3 years ago
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