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dalvyx [7]
3 years ago
14

The "normal" lead content in human blood is about 0.40 part per million (i.e., 0.40 g of lead per million grams of blood). A val

ue of 0.80 part per million (ppm) is considered to be dangerous. How many grams of lead are contained in 6.0 x 10^3 g of blood (the amount in an average adult) if the lead content is 0.62 ppm?
Chemistry
2 answers:
Reil [10]3 years ago
7 0

Answer:

in 6.0 E3 g of blood at a concentration of 0.62 ppm there are  3.5g of lead content

Explanation:

  • blood density: 1.06 g/L
  • ppm ≡ mg Pb / L blood

⇒ V blood = 6.0E3gblood * L / 1.06gblood = 5660.37 L blood

<u> mass of lead:</u>

⇒ 5660.37 L blood * 0.62 mg Pb / L blood * 0.001 g / mg

⇒ mass = 3.509 g of lead

djyliett [7]3 years ago
7 0

Answer:

3.7 × 10⁻³ g Pb

Explanation:

0.62 parts per million means that there are 0.62 g of lead per million grams of blood (10⁶ grams of blood). In order to find the grams of lead on 6.0 × 10³ grams of blood (the amount in an average adult), we will use a conversion fraction.

6.0 × 10³ g blood × (0.62 g Pb/ 10⁶ g blood) = 3.7 × 10⁻³ g Pb

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In a lab, silver nitrate,AgNO₃, is dissolved in water until no solid is observed in the container. Then, a solution of sodium ch
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The answer to your question is: A, C, E

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After reading the information given, we can conclude that both reactants react to form a new solid product and another product that do not precipitate.

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This option is not correct, in this process silver nitrate is dissolving in water but it is not a chemical reaction because matter does not change is nature.

e. A chemical reaction occurred when the solutions were combined  This option is true because silver nitrate and sodium chloride react to form a new product (solid formation and change in color).

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6 0
3 years ago
For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance th
Debora [2.8K]

Hey there!:

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C% =  ( atomic mass C / molar mass CHCl3 ) * 100

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H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

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Cl % ( molar mass Cl3 / molar mass CHCl3 ):

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Cl% =  ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%


Hope that helps!

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