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dalvyx [7]
3 years ago
14

The "normal" lead content in human blood is about 0.40 part per million (i.e., 0.40 g of lead per million grams of blood). A val

ue of 0.80 part per million (ppm) is considered to be dangerous. How many grams of lead are contained in 6.0 x 10^3 g of blood (the amount in an average adult) if the lead content is 0.62 ppm?
Chemistry
2 answers:
Reil [10]3 years ago
7 0

Answer:

in 6.0 E3 g of blood at a concentration of 0.62 ppm there are  3.5g of lead content

Explanation:

  • blood density: 1.06 g/L
  • ppm ≡ mg Pb / L blood

⇒ V blood = 6.0E3gblood * L / 1.06gblood = 5660.37 L blood

<u> mass of lead:</u>

⇒ 5660.37 L blood * 0.62 mg Pb / L blood * 0.001 g / mg

⇒ mass = 3.509 g of lead

djyliett [7]3 years ago
7 0

Answer:

3.7 × 10⁻³ g Pb

Explanation:

0.62 parts per million means that there are 0.62 g of lead per million grams of blood (10⁶ grams of blood). In order to find the grams of lead on 6.0 × 10³ grams of blood (the amount in an average adult), we will use a conversion fraction.

6.0 × 10³ g blood × (0.62 g Pb/ 10⁶ g blood) = 3.7 × 10⁻³ g Pb

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Answer:

I would say C

Explanation: Hope this helped

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Explanation:

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3 years ago
A 5.5 × 10–3 M solution of fluoroacetic acid, CH2FCOOH, has a pH of 2.57. What is the acid-dissociation constant, K a, of this a
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The acid dissociation constant is 1.3 × 10^-3.

<h3>What is acid-dissociation constant?</h3>

The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;

Let the acid be HA;

                  HA       +      H2O ⇄      H3O^+      +      A^-

since the pH of the solution is 2.57 then;

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Ka = 1.3 × 10^-3

Learn more about acid-dissociation constant: brainly.com/question/9728159

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Answer:

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