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Katen [24]
3 years ago
7

I don’t know what to do

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

original points (-2,0), (2,0), (0,2)

new points (-6.25,0),(6.25,0),(0,6.25)

the point (0,6.25) is the vertex that lies on y -axis

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Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.
VladimirAG [237]
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
7 0
3 years ago
Marley runs 5 yards down the track from point A to point B, and then stops and runs
julia-pushkina [17]

Answer:

\sqrt{61}=AC or 7.8102=AC

Step-by-step explanation:

If we connect a line from point A to point C we create a triangle, and we can use pythagorean theorem to find this distance. So the line from point A to point C will be our hypotenuse and the other two distances will be out side lengths.

5^{2}+6^{2}=AC^{2}

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\sqrt{61}=AC or 7.8102=AC

3 0
3 years ago
Please help! the question is in the attarchment!
DaniilM [7]

Answer:

1000( l + b)

Step-by-step explanation:

2(500l + 500b)

=500 (2(l+b))

=1000

8 0
3 years ago
Find f(2) given f(x) = -3x^3 + x^2 – 3
aleksley [76]

Answer:

D

Step-by-step explanation:

f(x) = -3x^3 + x^2 – 3       f(2) means that wherever you see a x, put in a 2.

f(2)= -3(2)^3 + (2)^2 - 3

f(2) = -3*8 + 4 - 3

f(2) = - 24 + 1

f(2) = - 23

6 0
2 years ago
Read 2 more answers
Fill in the blanks:
lys-0071 [83]
Reflection across the x-axis, followed by a, ?
3 0
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