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konstantin123 [22]
3 years ago
13

Help please :) (asap)

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0

Answer: x - 6

Step-by-step explanation:

ryzh [129]3 years ago
4 0

x^2 - x - 6= 0

(x - 3) ( x + 2) = 0

Equating

x - 3 = 0

x = 3

x+ 2= 0

x = -2

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) the top and bottom margins of a poster are 4 cm and the side margins are each 5 cm. if the area of printed material on the pos
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If x represents the width of the poster (including borders), the area of the finished poster can be written as
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
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It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the
son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that p = 0.5

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094

P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188

P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734

P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188

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85.56% probability that less than 6 of them have a high school diploma

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