Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
SA=94
Step-by-step explanation:
SA= 2(4*5) + 2(4*3) + 2(5*3)
SA=2(20) + 2(12) + 2(15)
SA=40 + 24 + 30
SA=94
Answer:
7.2
Step-by-step explanation:
a good method towards percentages in multiplying both numbers in this case 48 and 15 and then lowering the product by 2 decimal places
Answer:
9.6
Step-by-step explanation:
Use the Pythagorean Theorem
a² + b² = c²
Plug in the knowns
a² + 22² = 24²
Subtract 22² from both sides
a² = 24² - 22²
a² = 576 - 484
a² = 92
Take the square root of both sides
a = 9.591663046625438
Rounded
a = 9.6 ft
Median: middle number
Mean: average
How to calculate the median:
1) line the numbers in order from least to greatest
0 1 2 4 5 24
(you do not need to write all the fours or fives, one four or five is enough to represent it)
2) Next, take one number off each end at a time until you have one number in the middle left (if there are two numbers left in the middle, add them together, than divide them by two)
3) The median is 4 becuase it is in the middle.
How to calculate the mean:
1) Add all the numbers together
0+24+1+4+5+2+5+4 = 45
2) Now we divide 45 by 8 because there are eight numbers in the list
45/8 = 5
3) The mean is 5.
Answer: Median = 4, Mean = 5
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