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Yuliya22 [10]
3 years ago
13

the radius of the Outer Circle is 2x cm and the radius of the inside circle is 6 cm the area of the Shaded region is 288 Pi cent

imeters squared. What is the value of x
Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0

For this case we have that by definition, the area of a circle is given by:

A = \pi * r ^ 2

Where:

r: It is the radius of the circle.

So, we have that the area of the shaded region is given by:

\pi * (2x) ^ 2- \pi * 6 ^ 2 = 288 \pi\\4x ^ 2-36 = 288\\4x ^ 2 = 288 + 36\\4x ^ 2 = 324

We divide between 4 on both sides of the equation:

x ^ 2 = 81

We apply root to both sides:

x = \pm \sqrt {81}

We choose the positive value of the root:

x = \sqrt {81}\\x = 9

Finally, the value of "x" is 9

Answer:

x = 9

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Answer:

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Step-by-step explanation:

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Given that:

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c = c

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10b^2 - 9b^2 + 18b - 24b + 9 - 16 = 0

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b^2 +b-7b-7=0

Factorize:

b(b+1)-7(b+1) =0

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Split:

b - 7 = 0\ or\ b+1=0

b = 7\ or\ b=-1

But the adjacent of a triangle can't have a negative measurement.

So:

b = 7

Recall that:

c = 4 + 3b

a = 3 + 3b

Substitute 7 for b in the above expressions

c = 4 + 3 * 7

c = 4 + 21

c = 25

a = 3 + 3 * 7

a = 3 + 21

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Hypotenuse = 25cm

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