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Yuliya22 [10]
3 years ago
13

the radius of the Outer Circle is 2x cm and the radius of the inside circle is 6 cm the area of the Shaded region is 288 Pi cent

imeters squared. What is the value of x
Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0

For this case we have that by definition, the area of a circle is given by:

A = \pi * r ^ 2

Where:

r: It is the radius of the circle.

So, we have that the area of the shaded region is given by:

\pi * (2x) ^ 2- \pi * 6 ^ 2 = 288 \pi\\4x ^ 2-36 = 288\\4x ^ 2 = 288 + 36\\4x ^ 2 = 324

We divide between 4 on both sides of the equation:

x ^ 2 = 81

We apply root to both sides:

x = \pm \sqrt {81}

We choose the positive value of the root:

x = \sqrt {81}\\x = 9

Finally, the value of "x" is 9

Answer:

x = 9

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2x-7y=12 for y answer please​
Marat540 [252]

Answer: If you want mx + b= y form and you want the y intercept, then the answer would be 2x/7 - 12/7 = y. The y intercept is b, so it is 12/7.

Step-by-step explanation: 2x - 7y = 12

Move -7y to the other side: 2x= 12 + 7y

Subtract 12 to the left side: 2x - 12 = 7y

Then divide 7 into everything: 2x/7 - 12/7 = 7y/7

The 7s in the right side cancel out, so the equation is now: 2x/7 - 12/7 = y

The y intercept is b, which is the second term in the equation, so the

Y Equals : 12/7

I hope this is what you are looking for!  

6 0
3 years ago
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S=2WH+2WL+2HL SOLVE FOR L
RSB [31]
2WH+2WL+2HL=S\\\\2WL+2HL=S-2WH\\\\L(2W+2H)=S-2WH\\\\\boxed{L=\frac{S-2WH}{2W+2H}}
6 0
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What is the median of the set of data 928, 834, 842, 841, 932, 917, 892, 856, 908, 867, 873, 868, 872, 921, and 924?
Aleksandr-060686 [28]
Median: 873
Mean: 885
3 0
3 years ago
Will Mark Brainlest Help Please ,,,,<br> find the value of x and y ​
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Step-by-step explanation:

(-1,0),m=2

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4 0
3 years ago
determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+
Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0

Hence the lines are not intersecting nor parallel, they must be skew.

6 0
3 years ago
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