Answer:
Scruffy is
inches longer than Fluffy.
Step-by-step explanation:
Length of Scruffy =
inches
Length of Fluffy =
inches
We have to calculate how much Scruffy is longer than Fluffy.
Difference of their lengths = 
= (10 - 8) + 
= 2 + 
= 2 + 
=
inches
Therefore, Scruffy is
inches longer than Fluffy.
Answer:
subtract 2a + 3b - 3b =5 - 3b
simply 2a = 5 -3b
divide both sides by 2 . 2a over 2 = 5 over 2 - 3b over 2
simply a= 5- 3b over 2
Answer:
The partial fraction decomposition is
.
Step-by-step explanation:
Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.
To find the partial fraction decomposition of
:
First, the form of the partial fraction decomposition is

Write the right-hand side as a single fraction:

The denominators are equal, so we require the equality of the numerators:

Expand the right-hand side:

The coefficients near the like terms should be equal, so the following system is obtained:

Solving this system, we get that
.
Therefore,

Answer:
x = 8√3
Step-by-step explanation:
Using the Pythagorean Theorem:
a² + b² = c²
x² + 8² = 16²
x² + 64 = 256
x² = 192
√x² = √192
x = √64 √3
x = 8√3