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2 years ago

Arc JK is congruent arc LM. What is the length of chord LM? A. 2 B. 15 C. 16 D. 30

1 answer:

5 0

There is no way to determine the length LM if you don't have any information for the arc lengths. If you would like help you need to attach an image or post information...

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Which graph represents a function with direct variation

vazorg [7]

Answer:

WHere are the graphs

Step-by-step explanation:

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3 years ago

Find a three digit number. The tens digit is 3 time the hundreds digit. The sum of the digits is 15. If you reverse the digits,

tresset_1 [31]

Answer:

number = 267

Step-by-step explanation:

i am a 3 digit number divisible by 3.

100a + 10b + c

my tens digit is 3 times as great as my hundreds digit

b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9

and the sum of my digits is 15.

a + b + c = 15

if you reverse my digits i am divisible by 6 and 3

100c + 10b + a

this is a logic problem, an equation won't help us here

From the given information b = 3a, and the sum of the 3 digits = 15, we have:

1 3 ___; three single digits can't add up to 15

2 6 _7_; this has to be the number

3 9 _3_; reverse number is not different

Check for division by 3 and 6

267/3 = 89

762/6 = 127

267 is the number

3 0

2 years ago

The photo down below will show you what I need help with.

Irina18 [472]

Answer:

$\frac{x+7}{3}$ (the second option)

Step-by-step explanation:

Hope this helps!

7 0

3 years ago

Need quick answers please

Olenka [21]

Answer:

A, E, F, D

Step-by-step explanation:

Done this before

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2 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

<em>Hence the projection of b unto a is expressed as </em> $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$ <em></em>

7 0

3 years ago