Hello : the system is :
<span> y= -2x+4 ...(1)
y= x² +4x+13....(2)
x²+4x+13 = -2x+4
x²+6x+9=0
(x+3)² =0
x+3=0
x= -3
subsct in (1) : y=-2(-3)+4 =10</span>
<u>Answer-</u>
<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>
<u>Solution-</u>
The given polynomial is,
The zeros of the polynomials are,
Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1
Answer: true
Step-by-step explanation:
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount borrowed
From the information given,
P = 5000
r = 9
5.5% = 5.5/100 = 0.055
Assuming they are 365 days in a year
n = 365 because it was compounded 52 times in a year.
t = 29/365 = 0.0794
Therefore,
A = 5000(1 + 0.055/365)^365 × 0.0794
A = 5000(1 + 0.00015)^29
A = 5000(1.00015)^29
A = $5022
1 is 4/5=8/10=16/20
2 is 9/2=18/4=3616
3 is 11/12=22/24= 44/48
4 is 6/10=12/20=24/40
5 is 8/6=16/12=32/24
6 is 3/7=6/14=12/142
