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Flauer [41]
3 years ago
9

Can someone help me with number 6?

Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

The answer to your question is:

a) sinФ = -4/√17

b) cosФ= 1/√17

c) tanФ = -4

Step-by-step explanation:

Just draw a right triangle where the opposite leg is -4/√17 the adjacent leg is 1/√17 and the hypotenuse is 1.

then sine Ф = opposite / hypotenuse   = -4/√17 / 1 = -4/√17

      cosine Ф = adjacent /hypotenuse = 1/√17 / 1 = 1/√17

      tan Ф = opposite / adjacent  = -4/√17 /  1/√17 = -4/1

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I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

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And the quadratic formula is:

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So, first step is to compare the given equation with the above equation to get the value of a, b and c.

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Next step is to plug in these values in the above formula. Therefore,

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5 0
3 years ago
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