Answer:
Answer is the 2nd multiple choice question
Step-by-step explanation:
C (1,8) and (4,5). To interpret a system of equations when shown a graph, look for the points at which the two function intersect or meet. in this case they meet at both points (1,8) and (4,5)
We are given that the insect can lift 1.182 x 10^3 times
it's own weight. Say that w is weight, so the lift is:
lift = 1.182 x 10^3 * w
Assuming that your body weight is 60 kg, therefore you
can lift:
lift = 1.182 x 10^3 * 60 kg = 70,920 kg
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
It is A hope this helps :)