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3 years ago

A tortoise is walking in the desert. It takes

Mathematics

2 answers:

LiRa [457]3 years ago

8 0

1.6 meters per minute

work:
6.4meters/ 4 minutes = 1.6 meters per minute

dlinn [17]3 years ago

7 0

96 meters per hour :)

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Graph solve for y 5y-x=20

Tomtit [17]

$5y-x=20$ add x to both sides

$5y=x+20$ divide both sides by 5

$\boxed{y=\dfrac{1}{5}x+4}$

It's the equation of a line. We need only two points to the plot the graph.

Choice any two values of x. Put them to the equation of a line and calculate the values of y.

for x = 0:

$y=\dfrac{1}{5}(0)+4=0+4=4\to(0,\ 4)$

for x = 5:

$y=\dfrac{1}{5}(5)+4=1+4=5\to(5,\ 5)$

3 0

2 years ago

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Kesha had a recipe that required 1/3 pound of beef. 1 pound = 453.6 grams About how many grams of beef does she need

chubhunter [2.5K]

151.2 pounds of beef :)

3 0

3 years ago

Read 2 more answers

Need help !! Thanks !!!!!

mojhsa [17]

Your Right Answer is A good luck

5 0

3 years ago

#1: Write the equation of the graphed line. NO SPACES, ALL LOWERCASE. Please help

ivanzaharov [21]

Answer:

Equation of graphed line is $\mathbf{y=\frac{2}{3}x-3}$

Step-by-step explanation:

We need to write the equation of the graphed line.

The equation will be in slope intercept form $y=mx+b$ where m is slope and b is y-intercept

We need to find slope and y-intercept.

Finding slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We will use points (0,-3) and (3,2)

Looking at the graph, we get $x_1=0, y_1=-3, x_2=3, y_2=-1$

Putting values in graph and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-1-(-3)}{3-0} \\Slope=\frac{-1+3}{3} \\Slope=\frac{2}{3}$

So, we get slope $\mathbf{\frac{2}{3} }$

Finding y-intercept

y-intercept can be found when x is zero.

So, looking at graph, when x =0, y=-3

So, y-intercept is -3

Equation of Line

So, equation of line having slope $\mathbf{\frac{2}{3} }$ and y-intercept b = -3

$y=mx+b\\y=\frac{2}{3}x-3$

So, Equation of graphed line is $\mathbf{y=\frac{2}{3}x-3}$

8 0

3 years ago

On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump

rodikova [14]

To solve this question, you need to find how long jump is. For 2m high with 1.67 m/s2 it would be:

h= 1/2 gt^2
2= 1/2 * (1.67) t^2
t^2= 1.67
t= 1.29

If the speed is 20 mph and the jump is 2 second, the distance traveled would be:
20 miles/ hour * 1.29 second * (1 hour/3600second)= 0.007179 miles

If you need to convert it to meter then: 0.007179 mile * 1609.34meter/ mile= 11.55 meter

8 0

3 years ago