Given:
child = 2 forks
adult = 5 forks
total number of forks = 2992
total number of people = 764
c + a = 764
2c + 5a = 2992
find the value of c using the 1st equation.
c = 764 - a
substitute c in the 2nd equation by its value
2c + 5a = 2992
2(764-a) + 5a = 2992
1528 - 2a + 5a = 2992
1528 + 3a = 2992
3a = 2992 - 1528
3a = 1464
3a/3 = 1464/3
a = 488
c = 764 - a
c = 764 - 488
c = 276
child = 276 ; adult = 488
2c + 5a = 2992
2(276) + 5(488) = 2992
552 + 2440 = 2992
2992 = 2992
Hello! The subscription is a fixed price of 5.95 per month, and prints are $0.19 each. Let’s make an equation for this type of situation. 5.95 + 0.19x = 15.83. First off, let’s subtract 5.95 from both sides. When you do, you get 0.19x = 9.88. Now, divide each side by 0.19 to isolate the variable. 9.88/0.19 is 52. x = 52. There. Alazea purchased 52 prints in October.
Diagram D and are you in school
Answer:
37.5
Step-by-step explanation:
Let the length of the shorter piece be x and the longer piece be 5x.
Short piece + Long piece = 285 inches
x + 5x = 225
6x = 225
x = 225 ÷ 6
x = 37.5
Answer:
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Step-by-step explanation:
We must convert the given temperatures from degrees Celsius to degrees Fahrenheit
The formula is:
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Where C is the temperature in degrees Celsius and F is the temperature in degrees Fahrenheit
Then we must replace the temperature in degrees Celsius and solve the equation for F
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




The Fahrenheit temperature range in which the antifreeze protects the car is:
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