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Scilla [17]
3 years ago
13

Write each ratio in simplest fractional form. 1. 16 dogs and 9 cats 2. 99 miles to 6 gallons 3. 4 frogs to 9 lily pads 4. 6 cups

of milk to 4 cups of flour 5. 6 girls to 13 boys
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

1. 16/9

2. 33/2

3. 4/9

4. 3/2

5. 6/13

Step-by-step explanation:

1. 16 dogs and 9 cats  

16/9

2. 99 miles to 6 gallons  

99/6

Divide by 3 on the top and bottom

33/2

3. 4 frogs to 9 lily pads

4/9

4. 6 cups of milk to 4 cups of flour

6/4

Divide the top and bottom by 2

3/2

5. 6 girls to 13 boys

6/13

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A fish tank in the shape of a rectangular prism holds 30 cubic feet of water .the tank has a length of 5 feet and width of 3 fee
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Answer:

A - 2 feet

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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There are 321 crayons in a box and 204 crayons on the floor. About how many fewer than 1,000 crayons are there? Estimate. Then s
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3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

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area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

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V=\frac{3\sqrt{3} }{2} x^3 units^3


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3 years ago
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