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musickatia [10]
3 years ago
13

6. Homer and Bart plan to buy one computer for $499.00 strictly for gam purposes. Games cost $49.99 each. Part A: Define each va

riable and write an algebraic expression to describe how much they will spend before sales tax, based purchasing the computer and the number of games.
Mathematics
2 answers:
balandron [24]3 years ago
4 0

Answer:

The required algebraic expression is y=499.00+49.99x where x is the number of games and y is the total cost.

Step-by-step explanation:

Consider the provided information.

It is given that the cost price of computer is $499.00

Let x represents the number of games Homer and Bart bought and y is the total purchasing cost of the computer (before sales tax).

It is given that the cost of each game is 49.99.

If they bought x games, then the total cost will be:

y=499.00+49.99x

Therefore, the algebraic expression is y=499.00+49.99x where x is the number of games they bought and y be the total cost.

Kobotan [32]3 years ago
3 0

Answer:

T= 499.00 + 49.99g

Step-by-step explanation:

T=is total cost

G=is number of games

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-x^{2}+16x-60 = 0
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Hey i am just clueless
borishaifa [10]

Answer:

x = 14

y = 6

Step-by-step explanation:

<em>*</em><em>Property</em><em>*</em>

In a parallelogram:

Opposite sides are equal.

Since, the given figure is a parallelogram we can apply this property and equate:

  • 1) 2y + 1 = 13
  • 2) x = y + 8

<u>1) 2y + 1 = 13</u>

<em>subtracting</em><em> </em><em>1</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

=> 2y + 1 - 1 = 13 - 1

=> 2y = 12

<em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>2</em><em>:</em>

=> 2y/ 2 = 12/ 2

<em>On</em><em> </em><em>the</em><em> </em><em>LHS</em><em>,</em><em> </em><em>2</em><em> </em><em>gets</em><em> </em><em>canceled</em><em> </em><em>because</em><em> </em><em>it's</em><em> </em><em>available</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>numerator</em><em> </em><em>as</em><em> </em><em>well</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>denominator</em><em> </em>

<em>On</em><em> </em><em>the</em><em> </em><em>RHS</em><em>,</em><em> </em><em>2</em><em> </em><em>gets</em><em> </em><em>canceled</em><em> </em><em>when</em><em> </em><em>12</em><em> </em><em>is</em><em> </em><em>factorised</em><em> </em><em>to</em><em> </em><em>6</em><em> </em><em>×</em><em> </em><em>2</em><em>:</em>

<h3>=> y = 6</h3>

<u>2</u><u>)</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>y</u><u> </u><u>+</u><u> </u><u>8</u>

We've got the value of y from equation 1).

<em>Substituting it here:</em>

=> x = 6 + 8

<h3>=> x = 14 </h3>

Answer:

Hence, we got the values of x and y as:

\mathsf{x = 14  }\\  \mathsf{ y = 6}

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2 years ago
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