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torisob [31]
3 years ago
10

For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative

3 right angle​,calculate proj Subscript Bold v Baseline Bold uand sca l Subscript Bold v Baseline Bold u.
Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = -8(1)+0(3)+1(-3)\\= -11

Projection of U on V =\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }

Similarly projection of V on U

=\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }

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1. To the nearest degree, find the measure of angle A.
Assoli18 [71]

Answer:

(1) Option A is correct , The measure of angle A = 26°

(2) Option D is correct, The measure of angle B  =70°

Step-by-step explanation:

(1)

In a right angle triangle figure-1 ,

* Hypotenuse(H) is always opposite the right angle and it is always the longest side of the triangle.

* Adjacent side (B) is the non-hypotenuse side that is next to a given angle A.

* Opposite side(P) is across from a given angle A.

To find the Angle A we use the Cosine ratio:

Cosine ratio states that the ratio of the adjacent side of a right triangle to the hypotenuse.

By definition of cosine ratio we have;

\cos A = \frac{B}{H}                      ....[1]

In the figure - 1 we have B = 18 in and H = 20 in

substitute these in [1] to find angle A

\cos A =\frac{18}{20} =\frac{9}{10} = 0.9

or

A = cos^{-1} (0.9)

⇒ A \approx 26^{\circ}

therefore, the measure of angle A is,  26^{\circ}

(2)P

In figure -2

Find the measure of angle B.

First find the side BC, using Pythagoras theorem;

Pythagoras theorem states that in the right angle triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Apply Pythagoras theorem in rt. angle ABC;

AB^2 = AC^2+BC^2

Substitute the values of AB = 5.1 cm and AC =4.8 cm to solve for BC

(5.1)^2=(4.8)^2 +BC^2

26.01 = 23.04+BC^2

Simplify:

BC^2 = 2.97 or

BC = \sqrt{2.97} =1.723 cm

Now, find the angle B, using tangent ratio;

Tangent ratio states that the ratio of the Opposite side of a right triangle to the adjacent side.

\tan B = \frac{AC}{BC} =\frac{4.8}{1.732} =2.772

B = \tan^{-1} (2.772) \approx 70^{\circ}

Therefore, the measure of angle B is; 70^{\circ}.

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