<h2>Um I think its 143 i think im just guessing</h2>
4:1.
56,000÷2 = 28,000
14,000÷2 = 7,000
28,000/7,000 = 28/7
28 ÷ 7 = 4
---- -----
7 ÷7 = 1
4:1
Hope this helps!
Answer:
the answer is C
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
-3(x-p)2+g=0
-3x2+12x=10
-3(x2-4x)=10
-3(x2-4x+4)=10+12
x2-4x+4 = (x-2)2
-3(x-2)2=22
-3(x-2)2-22=0
q = -22
Presumably you want to find
![B^C\cup A](https://tex.z-dn.net/?f=B%5EC%5Ccup%20A)
, where
![B^C](https://tex.z-dn.net/?f=B%5EC)
presumably denotes the complement of
![B](https://tex.z-dn.net/?f=B)
. We have
![S=A\cup B\cup D=\{2,9,13,28,40\}](https://tex.z-dn.net/?f=S%3DA%5Ccup%20B%5Ccup%20D%3D%5C%7B2%2C9%2C13%2C28%2C40%5C%7D)
and since
![B=\{9,13,28\}](https://tex.z-dn.net/?f=B%3D%5C%7B9%2C13%2C28%5C%7D)
, we have
![B^C](https://tex.z-dn.net/?f=B%5EC)
the set of all values in
![S](https://tex.z-dn.net/?f=S)
*not* in
![B](https://tex.z-dn.net/?f=B)
; that is,
![B^C=\{2,40\}](https://tex.z-dn.net/?f=B%5EC%3D%5C%7B2%2C40%5C%7D)
.
Now