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kipiarov [429]
3 years ago
7

Also this question tooo pleease, PS: what topic is this Solve for x.

Mathematics
1 answer:
MrRissso [65]3 years ago
8 0

This falls under geometry. The two labeled angles are congruent, which means the line segment between them (AD in the image) is a bisector of the angle at vertex A. Use the angle bisector theorem, which says that

\dfrac{BD}{DC}=\dfrac{AB}{AC}\iff\dfrac{12}{(5+9x)-12}=\dfrac{15}{25}

\dfrac{12}{9x-7}=\dfrac35

20=9x-7

x=3

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Lelu [443]

Answer:

x=-6

Step-by-step explanation:

9x-3x=-36

6x=-36

x=-6

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Which of the following could be the equation of a line parallel to the line y=-4x+1
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Help is appreciated! Thanks!
sukhopar [10]

Answer:

  1. 16√3
  2. -45+15i
  3. √255
  4. 6√2 +3√10

Step-by-step explanation:

1)

-4i\sqrt{-48}=-4i\sqrt{(-1)(4^2)(3)}=(-4i)(4i)\sqrt{3}=16\sqrt{3}

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2)

(-5-5i)(3-6i)=-5(3-6i)-5i(3-6i)=-15+30i-15i+30i^2=-15-30+15i\\\\=-45+15i

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3)

\sqrt{3}\sqrt{5}\sqrt{17}=\sqrt{3\cdot 5\cdot 17}=\sqrt{255}

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4)

\sqrt{3}(\sqrt{24}+\sqrt{30})=\sqrt{3\cdot 24}+\sqrt{3\cdot 30}=\sqrt{6^2\cdot 2}+\sqrt{3^2\cdot 10}\\\\=6\sqrt{2}+3\sqrt{10}

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The applicable identities are ...

\sqrt{a^2b}=a\sqrt{b}\\\\i^2=-1

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xz_007 [3.2K]

Answer:

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Step-by-step explanation:

All work is shown above.

I am joyous to assist you anytime.

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3 years ago
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