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3 years ago

Give the slope lf y -3 =4(x+8) and point on the line.

Mathematics

1 answer:

Olenka [21]3 years ago

6 0

Answer:

slope = 4

Step-by-step explanation:

slope is the coefficient attached to the x variable: thus the 4

so slope is 4 after you distribute the 4 to x and 8 and add 3

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How many ounces are in 8 cups

Olenka [21]

First ask your self how many ounces are in 1 cup?
8 ounces
So to find how many ounces are in 8 cups, you have to multiply how many ounces in one cyp (8) by 8
8×8=64
64 ounces

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3 years ago

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What is the answer for question #8

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

5 + 1 = 6 + 8.

Here how I explain it, You are adding each number to get you answer but.

6 + 8= 14

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3 years ago

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leva [86]

Step-by-step explanation:

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2 years ago

Please hurry! 8. Write in your own words what happens to the

Blizzard [7]

X-Axis
When a figure flips over the X-axis, the X coordinate stays the same while the Y-coordinate’s sign is flipped.

Y- axis

When a figure is flipped over the Y- axis the Y coordinate stays the same while the X axis coordinate’s sign is flipped

Example- (x,y)
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(2,5) —> (2,-5)

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3 years ago

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Find the exact value of tan(165°) using a difference of two angles

Katyanochek1 [597]

Answer: $-2+\sqrt{3}$

=========================================================

Work Shown:

Apply the following trig identity

$\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\$

Now let's rationalize the denominator

$\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\$

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

$\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949$

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as $\sqrt{3}-2$ but it's the same as above.

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3 years ago