104 = -16T2 + 729
16t^2 = 729 - 104 = 625
4t = +/-25
t = +/-6.25
Between 6.25 and 13.5 seconds after he jumps
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
2y*3x+46
3x+46=2y
(3x+46)/2=y
3/2x+23=y
y=3/2x+23
Answer:
I think 4^0 is the answer
Answer:
36
Step-by-step explanation:
28+8=36
8+8=16
BOOM GOT A BRAIN lol
