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satela [25.4K]
3 years ago
9

I need some help this math problem

Mathematics
2 answers:
EastWind [94]3 years ago
5 0

Answer: i think it is 2/7

Step-by-step explanation:

Sunny_sXe [5.5K]3 years ago
5 0
The answer for your question is 2/7
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Blake said 4/5+1/3 =5/8 does his answer make sense explain. please help
Tatiana [17]
Hey there!

The answer is no because whenever you add or subtract fractions, you find the common denominator(the bottom of the fraction)

Corret way:
The common denominator is 15 (5*3)
Multiply numerator(top) and the denominator by 3 
4/5*3*3= 12/15
Multiply numerator and the denominator by 5
1/3*5/5= 5/15
So the equation is now
12/15+5/15= 17/15 or 1 2/15

Hope this helps! :)
7 0
3 years ago
What is the best estament of 12762
NeX [460]

Answer:

13000

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the intercept and graph the following linear equations: 2x+y=1
Dima020 [189]

Answer:

2(1)+y =1 for × intercept

2x+(1)=1 for y intercept

7 0
2 years ago
Help with q25 please. Thanks.​
Westkost [7]

First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.

Let's apply the first derivative of this f(x) function.

f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\

Now apply the derivative to that to get the second derivative

f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\

We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.

Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.

-----------------------------------

Let's compute dy/dx. We'll use f(x) as defined earlier.

y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\

Use the chain rule here.

There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.

Now use the quotient rule to find the second derivative of y

\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\

If you need a refresher on the quotient rule, then

\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\

where P and Q are functions of x.

-----------------------------------

This then means

\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\

Note the cancellation of -(f ' (x))^2 with (f ' (x))^2

------------------------------------

Let's then replace f '' (x) with -p^2*f(x)

This allows us to form  ( f(x) )^2 in the numerator to cancel out with the denominator.

\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\

So this concludes the proof that \frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\ when y = \ln\left(\sin(px)+\cos(px)\right)\\\\

Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.

7 0
2 years ago
What is the solution set of 6 x 2 - 24 = 0?
Aleks [24]

Brainliest please?

Answer: <u><em>no solution</em></u>

there is no solution set

Step-by-step explanation:

6 x 2 = 12

12 - 24 = -12

-12 is not equal to 0

there are no solutions

4 0
3 years ago
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