Question

Write a equation of a line perpendicular to the line below in point-slope from that passes through the point (-2,6)

Answer 1

Answer:

Option 1: $y-6=-4(x+2)$

Step-by-step explanation:

Find the slope of the perpendicular line by finding the negative reciprocal of the original slope. (Negative reciprocal = flip upside down and add a negative). So we get -4 for the perpendicular slope.

Next, we know the point (-2,6) is on the line, so we can get x=-2 and y=6.

Plug this into point-slope form: $y_{1}-y_{2}=m(x_{1}=x_{2})$

$y_{1} - (6)=-4(x_{1}-(-2))$

$y-6=-4(x+2)$