Applying the Laws of Sines and Cosines

Mathematics

1 answer:

Naddika [18.5K]3 years ago

4 0

Essentially, you would take the formula for the laws of sines and cosines: a^2=b^2+c^2-2bc(Cos(theta)). a is the unknown side you are solving for and theta is the opposite angle to a. Since the angle opposite to R is supplementary to the 50 degree angle, 180-50=130. b could be assigned to either of the given sides; the same goes for c (e.g. b=40 and c=38). Thus, the question should be straightforward in plugging in quantities and solving for the resultant force.

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Answer:

<em><u>1 and 5</u></em>

Step-by-step explanation:

The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:

$C=2\pi r$

Insert the radius:

$r=10\\C=2\pi *10$

Simplify pi:

$C=2*3.14*10$

Simplify multiplication:

$C=6.28*10\\C=62.8$

The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:

$P=10+10+10+10\\P=10+10+20\\P=10+30\\P=40$