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3 years ago

37 divided by 32.93=

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

7 0

Approximately 1.12 (1.1235955056)

Paha777 [63]3 years ago

5 0

Answer is 1.12359551. 1.12 if rounded.

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A mistake was made in mixing the lemonade—<br> PLEASE HELP!!

beks73 [17]

Answer:

Part A:

$4 + x = y$

$0.5*4 + 1*x = 0.7*y$

$x = 8/3\ quarts\ of\ 100\%\ solution$

$y = 20/3\ quarts\ of\ 70\%\ solution$

Part B:

$x + y = 10$

$2x + 3y = 23$

$x = 7$ and $y = 3$

Step-by-step explanation:

Part A:

The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:

$4 + x = y$

$0.5*4 + 1*x = 0.7*y$

Using the value of y from the first equation in the second one, we have:

$2 + x = 0.7*(4 + x)$

$2 + x = 2.8 + 0.7x$

$0.3x = 0.8$

$x = 8/3\ quarts$

$y = 4 + 8/3 = 20/3\ quarts$

Part B:

If he shoots a total of ten targets, we can write the equation:

$x + y = 10$

Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:

$2x + 3y = 23$

If we subtract the second equation by two times the first one, we have:

$2x + 3y - 2*(x + y) = 23 - 2*10$

$2x + 3y - 2x - 2y = 23 - 20$

$y = 3$

$x + 3 = 10$ ⇒ $x = 7$

4 0

3 years ago

110.94 as a percentage

-BARSIC- [3]

Answer:

Hey! I believe this is your answer:

11094%

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$