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3 years ago

HELP PLEASEEEEE WILL GIVE BRAINLIEST AND GOOD RATING!!!!

Mathematics

2 answers:

RSB [31]3 years ago

8 0

Answer:

1.5 is shown on the second line

Step-by-step explanation:

because it is in the middle of 1 and 2

torisob [31]3 years ago

7 0

Answer:

The second one

Step-by-step explanation:

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Find variable y<br> : -90=5y-20

NeTakaya

-90= 5y-20

-90+20= 5y-20+20

-70=-5y

-70/-5= -5y/-5

y= 14

7 0

3 years ago

A zoo train ride costs $3 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who took

PIT_PIT [208]

A=adult
c=children
total lumber=30
total number=adults+children
a+c=30

total cost=50
total cost=acost+ccost

acost=a times cost per adult=a times 3=3a
ccost=c times cost per child=c tiems 1=1c=c
total cost=3a+c
50=3a+c

equiaotn are
a+c=30
3a+c=50
multiplyu first by -1 and add
3a-a+c-c=50-30
2a=20
a=10
sub
10+c=30
c=20

answer is A

4 0

3 years ago

Read 2 more answers

Explain how to subtract 247 from 538

Vladimir79 [104]

8-7=1 3-4=1 5-2=3 So it is 311.

4 0

3 years ago

(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi

Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. $x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. $c = \dfrac{3}{8} \ g/L$

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx = (5·c - 5·c/3)×dt = 20/3·c = $6\frac{2}{3} \cdot c \cdot dt$

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$

$c = \dfrac{3}{8} \ g/L$

4 0

3 years ago

Help me please someone Thankss

olganol [36]

Answer:

Hope that helps!

Step-by-step explanation:

6 0

3 years ago