<img src="https://tex.z-dn.net/?f=4%20%5Ccos%20%7B%7D%5E%7B2%7D%20%20%3D%201" id="TexFormula1" title="4 \cos {}^{2} = 1" alt="4

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nevsk [136]

3 years ago

\cos {}^{2} = 1" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Furkat [3]3 years ago

6 0

Yo sup??

4cos²x=1

cos²x=1/4

cosx=±1/2

x=π/3 or x=2π/3

Hope this helps.

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3 years ago

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= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

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7 0

3 years ago