Answer:
4 toppings
Step-by-step explanation:
10 - 8 = 2
2 / .5 = 4
C is the answer cause 9 is the common factor
Answer:
cosec <W = 68/60
Step-by-step explanation:
Using SOH CAH TOA identity
sin theta = opposite/hypotenuse
sin<W = XV/WV
Get WV using pythagoras theorem
WV² = 32²+60²
WV² = 1024 + 3600
WV² = 4624
WV = 68
sin<W =60/68
Since cosec <W = 1/sin<W
cosec <W = 68/60
Your answer would be C. 6.07 × 10^24.
This is because to add numbers in standard form, we need to get their (×10^x) to be the same, as in, we need to get 7 × 10^22 to be [value] × 10^24.
To convert ×10^22 to ×10^24, we need to divide 7 by 100, as 0.07 × 10^24 = 7 × 10^22.
Now that we have them both with the same power, we can add 6 to 0.7 to get 6.07 × 10^24.
I hope this helps! Let me know if you have any questions because my explanation was a bit strange :)
Answer:
(a) 0.2721
(b) 0.7279
(c) 0.2415
Step-by-step explanation:
(a) If we choose only one student, the probability of being a math major is 
(because there are 5 math majors in a class of 18 students). So, the probability of not being a math major is 
(we subtract the math majors of the total of students).
But there are 4 students in the group and we need them all to be not math majors. The probability for each one of not being a math major is 
and we have to multiply them because it happens all at the same time.
P (no math majors in the group) = 
= 0.2721
(b) If the group has at least one math major, it has one, two, three or four. That's the complement (exactly the opposite) of having no math majors in the group. That means 1 = P (at least one math major) + P (no math major). We calculated this last probability in (a).
So, P (at least one math major) = 1 - P(no math major) = 1 - 0.2721 = 0.7279
(c) In the group of 4, we need exactly 2 math majors and 2 not math majors. As we saw in (a), the probability of having a math major in the group is 5/18 and having a not math major is . We need two of both, that's 
. But we also need to multiply this by the combinations of getting 2 of 4, that is given by the binomial coefficient 
.
So, P (exactly 2 math majors) = 
= 
= 0.2415
