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levacccp [35]
3 years ago
10

Match the equation with the correct property of equality by drawing a line.

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer: division , addition, addition, multiplication, subtraction, addition, multiplication

Step-by-step explanation: idrk know how to explain other than the fact that you look at the symbols.

You might be interested in
Select the measures of the angles of a triangle whose angles have measures in the ratio 6:8:10
morpeh [17]

Answer:

45, 60, 75

Step-by-step explanation:

The ratio of the angles are 6:8:10

Multiply by x to get the angle measures

6x, 8x,10x

We know the sum of the angles is 180 for a triangle

6x+8x+10x = 180

Combine like terms

24x = 180

Divide each side by 24

24x/24 = 180/24

x =7.5

Each angle is

6x = 6(7.5) =45

8x = 8(7.5) =60

10x = 10*7.5 = 75

4 0
3 years ago
If you take 2 1/2 tablets of meds 3 times a day for 10 days, how many tablets in total have you taken?
Alisiya [41]
This is how I solved it.
2.5 multiplied by 3 is 7.5, which equals how many she takes a day.
Then I multiplied 7.5 by 10 = 75. I did that because the meds are taken for 10 days. 
Also if you added 7.5 ten times is also 75.

So my final answer is that 75 tablets have been taken in total.

3 0
3 years ago
What does the expression n+3 represent?
Sati [7]
Do you know what n equals so i can solve it?<span />
5 0
4 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
What is the slope of the line?​
VladimirAG [237]

Answer:

-1

Step-by-step explanation:

Pick two points on the line

(0,1) and ( 2,-1)

Using the slope formula

m = (y2-y1)/(x2-x1)

    = ( -1 -1)/(2-0)

     = -2/2

    = -1

5 0
3 years ago
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