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White raven [17]
3 years ago
12

Help please, Thank you so much.

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
6 0

(a) (\frac{1x}{2} - \frac{1}{4}) and 5x^2 -2x-6

To find product ,

first multiply (\frac{1x}{2}) with 5x^2 -2x-6

(\frac{1x}{2})* (5x^2 -2x-6) = \frac{5x^3}{2} - x^2 -3x

Now  multiply (\frac{-1}{4}) with 5x^2 -2x-6

(\frac{-1}{4}) * (5x^2 -2x-6) = -\frac{5x^2}{4} + \frac{x}{2}  + \frac{3}{2}

Now we combine it

\frac{5x^3}{2} - x^2 -3x -\frac{5x^2}{4} + \frac{x}{2}  + \frac{3}{2}

\frac{5x^3}{2} - \frac{9x^2}{4} - \frac{5x}{2} + \frac{3}{2}

(b) No, the products are not same

Because (\frac{1x}{2} - \frac{1}{4}) is interchanged as (\frac{1x}{4} - \frac{1}{2}). when the terms are interchanged then the product will not be same


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<u>1. What is the difference?</u>

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<u>2. Work out the term before the first term.</u>

    The first term is 3, and we know that the sequence goes up by 5. So, to get the term before 3 we would add 5.

3 + 5 = 8   Remember, this is positive 8. (+8)

<u>3. Put that term at the end of the equation. </u>

   We have -5n already and we just worked out the term before the first one which is positive 8 - so put that at the end of the equation.

-5n + 8  This is our answer!

Just to prove it works:

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8 0
4 years ago
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