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jeyben [28]
3 years ago
14

Please help with the question on the picture!

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer: B I think :)

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3 years ago
The average of four different positive integers is 9. What is the greatest value for one of the integers?
saul85 [17]

From the given information; Let the unknown different positive integers be (a, b, c and d).

An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.

Suppose we make an assumption that (a) should be the greatest value of this integer.

Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.

Therefore, the average of this integers = 9

Mathematically;

\mathbf{\dfrac{(a+b+c+d)}{4} =9}

\mathbf{\dfrac{(a+1+2+3)}{4} =9}

\mathbf{\dfrac{(6+a)}{4} =9}

By cross multiplying;

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a = 36 - 6

a = 30

Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.

Learn more about integers here:

brainly.com/question/15276410?referrer=searchResults

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Step-by-step explanation:

Alsooo this is Mathematics not science

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