Circumference of a circle:
C = 2 r π;
Length of an arc:
L = r π α / 180°
L = r π · 30° / 180° = r π /6
r π /6 : 2 r π = 1/6 : 2 = 1/12
Answer: A ) 1/12
The triangle ABC is equilateral.
⇒ AB = BC = AC
6x - 3 = 5x ⇒ 6x - 5x = 3 ⇒ x = 3 cm
6x - 3 = 3x + 6 ⇒ 6x - 3x = 6 + 3 ⇒ 3x = 9 ⇒ x = 9/3 = 3 cm
5x = 3x + 6 ⇒ 5x - 3x = 6 ⇒ 2x = 6 ⇒ x = 6/2 = 3 cm
<h2>⇒⇒⇒ x = 3</h2>
AB 6x - 3 = 6 - 3 + 3 = 18 - 3 = 15
AC = 3x + 6 = 3 × 3 + 6 = 9 + 6 = 15 cm
BC = 5x = 5 × 5 = 15 cm
<h2>⇒⇒⇒ AB = AC = BC = 15 cm</h2><h2 /><h2 />
Answer:
C. 434π
Step-by-step explanation:
Given:
Radius (r) = 7 in.
Height (h) = 24 in.
Required:
Surface area of the cylinder
Solution:
S.A = 2πrh + 2πr²
Plug in the values
S.A = 2*π*7*24 + 2*π*7²
S.A = 336π + 98π
S.A = 434π
Answer:
See below.
Step-by-step explanation:
If the coordinates of E' were (a, b) the coordinates of the pre-image E would be (b, a).
y = x is the line so the coordinates will flip.
I really don't know, this is to difficult