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zaharov [31]
3 years ago
10

WHO EVER HELPS GET 18 POINTS AND BRAINLIEST ANSWER!

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

my test results

A city's water tower is in the shape of a sphere with a radius of 15 feet. If the tank is full, what is the exact value of the volume of the tank?

Selected Answer:

Incorrect 450π ft3

Correct Answer:

Correct 4500π ft3

Response Feedback:

Use the formula for volume of a sphere.

Question 2

1 out of 1 points

A basketball has a radius of 9 inches. What is the exact value of the volume of the ball?

Selected Answer:

Correct 972π in3

Correct Answer:

Correct 972π in3

Response Feedback:

Use the formula for volume of a sphere.

Question 3

1 out of 1 points

A lacrosse ball has a radius of 3 inches. Which value is closest to the volume of the ball? Use 3.14 for π.

Selected Answer:

Correct 113.04 in3

Correct Answer:

Correct 113.04 in3

Response Feedback:

Use the formula for volume of a sphere.

Question 4

1 out of 1 points

A geodesic dome has a radius of 27 feet. Which value is closest to the volume of the dome? Use 3.14 for π.

Selected Answer:

Correct 82,406 ft3

Correct Answer:

Correct 82,406 ft3

Response Feedback:

Use the formula for volume of a sphere.

Question 5

1 out of 1 points

The Epcot Center in Florida has a giant dome that is a sphere with a diameter of 165 feet. Which value is closest to the volume of the dome? Use 3.14 for π.

Selected Answer:

Correct 2,350,879 ft3

Correct Answer:

Correct 2,350,879 ft3

Response Feedback:

pantera1 [17]3 years ago
5 0
1. is 450ft, and #2. is 64ft. 
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The product of 4 and twice a number is 60
fredd [130]

Answer: I think the answer would be 4+2n=60.. might be wrong though

Step-by-step explanation:

6 0
3 years ago
Find the distance from P to l.
ki77a [65]
Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\

Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}
4 0
3 years ago
A candle on a table is 6 inches tall and burns at a rate of .8 inches per hour. How many hours will it take for the candle to bu
Vlada [557]

Answer:

6 hours

Step-by-step explanation:

6 inches burns at rate .8 inches in 1 hour

to be 1.2 inches has to burn 6 -1.2 = 4.8 inches of the candle

4.8 inches / .8 inches in 1 hour  = 6 hours

7 0
3 years ago
1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves
erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx

\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx

\ln|y| = x - \ln|x+1| + C

When x = 0, we have y = 2, so we solve for the constant C :

\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)

Then the particular solution to the DE is

\ln|y| = x - \ln|x+1| + \ln(2)

We can go on to solve explicitly for y in terms of x :

e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}

(b) The curves y = x² and y = 2x - x² intersect for

x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1

and the bounded region is the set

\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}

The area of this region is

\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}

7 0
2 years ago
Help asap please!
mario62 [17]
I have to rewrite the expressions because they look very confusing.

1) The given fractions to add are:

  4p² + 6        2p - 2
------------ +  ------------
     4p²             10p²

2) The statements to asses are:

<span>A) The least common denominator is 20p
.
B) The first fraction rewritten with the LCD is (20p² +30) / 20p²

C) The second fraction rewritten with the LCD is (4p - 4) / 20p

D) The sum is (24p² -4p +30 ) / 20p² = (12p-2p+15) / 10p^2

E) The sum is a rational expression.

This is the result for each statement.

</span>
<span>A) The least common denominator is 20p

FALSE: THE LCD IS 20p², because it the least expression that contains all the prime factors of both denominators: 4p² and 10p.

See that you cannot divide 20p by 4p² but you can divide 20p² by 4p² and 10 p. So, 20p is not a common denominator.
.
B) The first fraction rewritten with the LCD is (20p² +30) / 20p²

TRUE: you get this expression from the first fraction by multiplying both numerator and denominator by  20p² / 4p² = 5:

(4p² + 6)×5 = 20p² + 30

(4p²)×5 = 20p²

=>

  20p² + 30
--------------
      20p²

C) The second fraction rewritten with the LCD is (4p - 4) / 20p

FALSE: you have to multiply both numerator an denominator by 20p² / 10p = 2p

(2p - 2) × 2p = 4p² - 4p

10p × 2p = 20p²

So, the second fraction rewritten with the LCD is:

 4p² - 4p
-----------
    20p²

D) The sum is (24p² - 4p +30 ) / 20p² = (12p-2p+15) / 10p²

TRUE

</span>
<span><span>  20p² + 30        4p² - 4p         24p² - 4p + 30
-------------- +   --------------- = ----------------------
      20p²              20p²                    20p²</span>


And when you simplify the last fraction dividing by 2 you get:

  12p² - 2p + 15
-----------------------
          10p²

E) The sum is a rational expression.

TRUE:

The sum of rational number has the closure property which means that by adding rational expression you will always ge a rational expression.
</span>
6 0
3 years ago
Read 2 more answers
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