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ioda
3 years ago
6

What is the third quartile of this data set 20,21,24,25,28,29,35,36,37,43,44

Mathematics
2 answers:
dedylja [7]3 years ago
7 0

The third quartile is 37.Apex

SashulF [63]3 years ago
6 0

Answer:

37

Step-by-step explanation:

The data set is in ascending order, thus the median is the middle value of the data set.

median = 29

The third quartile is the middle value of the data to the right of the median

Q_{3} = 37

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Dimas [21]
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Then if  X, Y-12, Z form a Geometric sequence, it means X/Y-12=Y-12/Z which is the same as 2k/7k-12=7k-12/8k if we cross multply, we get
   16k²= 49k²-168k +144
  33k²-168k+144 =0 solving for k
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3 0
3 years ago
Find the 8th term of the geometric sequence 5, -15, 45
FrozenT [24]

Answer:

a₈ = - 10935

Step-by-step explanation:

the nth term of a geometric sequence is

a_{n} = a₁ (r)^{n-1}

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here a₁ = 5 and r = \frac{a_{2} }{a_{1} } = \frac{-15}{5} = - 3 , then

a₈ = 5 × (-3)^{7} = 5 × - 2187 = - 10935

6 0
2 years ago
A construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. If the buildi
Vlad1618 [11]

Let x represent the height of the model.

We have been given that a construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. We are asked to find the height of the model, if  the building is expected to be 200 feet tall.

We will use proportions to solve our given problem as:

\frac{\text{Model height}}{\text{Actual height}}=\frac{\text{Model length}}{\text{Actual length}}

Upon substituting our given values, we will get:

\frac{x}{200\text{ ft}}=\frac{3\text{ in}}{\text{32 ft}}

\frac{x}{200\text{ ft}}\times 200\text{ ft}=\frac{3\text{ in}}{\text{32 ft}}\times 200\text{ ft}

x=3\text{ in}\times 6.25

x=18.75\text{ in}

Therefore, the model will be 18.75 inches tall.

7 0
3 years ago
Solve for x: 4(x-2)+6=2(5x-6)
Katarina [22]

4(x - 2) + 6 = 2(5x - 6)     <em>use distributive property</em>

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8 0
3 years ago
Graph for f(x)=6^6 and f(x)=14^x
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Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0
3 years ago
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