1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leno4ka [110]
3 years ago
7

Predict the empirical formula of the ionic compound that forms from aluminum and oxygen.

Chemistry
1 answer:
sertanlavr [38]3 years ago
8 0

Answer:

A.   AlO

Explanation:

The empirical formula of a compound is the simplest possible formula giving the ratio of atoms in a molecule of the compound.

We know that Aluminium forms Al^{3+} and oxygen forms O^{2+}.

As such the formation of the ionic compound between a metal and non-metal results into Al_2O_3.

The empirical formula is as follows:

 Element                       Aluminium           Oxygen

% composition

by mass                              26.98                    16.0

mole ratio                           26.98/26               16/16

                                    =  1.04                              = 1

divided by the

smallest number            1.04/1                             1/1

                                        1.04                             1

The empirical formula is AlO

You might be interested in
For the procedural error, indicate if the error will affect the actual yield of copper(II) saccharinate product and if it does,
jolli1 [7]

Answer:

Lowers the actual yield

Explanation:

5 0
3 years ago
13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the
wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.</em>

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.</em>

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

3 0
3 years ago
What are the atoms of Fe(SCN)3
Igoryamba

Answer:

55.845

Explanation:

yep

5 0
3 years ago
Did I get This right I’m confused
Paul [167]
Hey bud !
You were close congrats !
the only problem i saw was the units part at the end.
remember volume is 3 dimensional
length width and height
so it is m^3
3 0
4 years ago
If you observe with the microscope that a cell contains chloroplasts can you conclude that this is a plant cell?
shusha [124]
Obviously since plant cell contains chloroplasts.
8 0
3 years ago
Other questions:
  • Which weak acid would be best to use when preparing a buffer solution with a ph of 9.20?
    14·2 answers
  • Potassium and sodium chloride are similar in charge and they both have the same anion.  When comparing sodium chloride (36 g / 1
    6·1 answer
  • How many atoms are in 1 mole of hydrogen
    14·1 answer
  • Study the animal in the image below. What can you infer about the animal from this image?
    10·1 answer
  • When 0.2 kg of gasoline undergoes combustion, 18500 kJ of energy are released. Express the heat released, 18500 kJ in calories.
    6·1 answer
  • The pH scale from 7 to 14 is for a(n) What .
    5·1 answer
  • 1. Which of the following best describes natural selection?
    7·1 answer
  • 6. The fusion of 4 H-1 nuclei to produce two positrons and one other nuclei.​
    15·1 answer
  • Hi, pls can someone answer<br> I'll give brainliest
    5·2 answers
  • What temperature creates hail
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!