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JulijaS [17]
4 years ago
11

Which expression is a prime polynomial?

Mathematics
1 answer:
kirill115 [55]4 years ago
7 0

Answer:

A polynomial is prime if it can not be factored into polynomials of lower degree also with integer coefficients.

For example, the first option:

x^3 + b*x^2 can be rewritten as:

(x - 0)*(x^2 + b*x)

So it is not prime.

The second option:

x^2 -4x - 12

Because here we can factor this into:

(x + 2)*(x - 6) = x^2 - 6x + 2*x - 12 = x^2  - 4x - 12

Now, the third option is a two variable polynomial, here the degree is equal to the sum of the degrees of both variables.

x^4 + 8*x*y^3

(x - 0)*(x^3 + 8*y^3)

So each side has a lower degree than the original polynomial, then it is not prime.

4th option:

x^2 - b^3

This can be written as:

(x + b^(3/2))*(x - b^(3/2))

Now, here we have a problem.

If for example, b = 1, this would not be a prime.

because 1^(3/2) = 1.

But if b^(3/2) is not an integer, then we can not factorize the initial polynomial into lower degree polynomials with only integer coefficients, then we can not be 100% sure that this is not a prime polynomial, then this is the correct option.

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Andre45 [30]

Answer is

X=30 z=68

3 0
3 years ago
Read 2 more answers
Consider the system of equations.
Harman [31]

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

The given system of equations:

x  +  2y  =  1............(1)

-3x - 2y  =  5..........(2)

This can be written in matrix form as shown:

\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Find the determinant of \left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]

\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle  = 4

\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12

\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8

x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3

y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

Learn more here: brainly.com/question/4428059

3 0
3 years ago
Kerry knit 16 winter hats to give as presents to her family. She wants to package the hats in gift boxes. She wants to put 5 hat
solniwko [45]

Answer:

she needs to buy 4 boxes since she can't buy a part of a box. assuming total boxes means completely filled boxes, then she fills 3

Step-by-step explanation:

7 0
3 years ago
-1/2 + ( 3/4 x 4/9)
SIZIF [17.4K]

Answer:

-1/6

Step-by-step explanation:

-1/2 + ( 3/4 x 4/9)

PEMDAS says parentheses first

Rearranging the fractions

-1/2 + ( 3/9 x 4/4)

-1/2 + (1/3*1)

-1/2 + 1/3

Getting a common denominator of 6

-1/2 *3/3 + 1/3 *2/2

-3/6+2/6

-1/6

5 0
4 years ago
Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

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3 years ago
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