Answer:
5 hours
Step-by-step explanation:
Lillian is deciding between two parking garages.
Let the time required to park be represented by t
A = Amount
From Garage A
A = the amount Garage A would charge if Lillian parks for t hours
B = the amount Garage B would charge if Lillian parks for t hours.
Garage A
Garage A charges an initial fee of $4 to park plus $3 per hour.
A = $4 + $3 × t
A = 4 + 3t
Garage B charges an initial fee of $9 to park plus $2 per hour.
B = $9 + $2 × t
B = 9 + 2t
The hours parked, t, that would make the cost of each garage the same is calculated by equating A to B
A = B
4 + 3t = 9 + 2t
Collect like terms
3t - 2t = 9 - 4
t = 5 hours
Therefore, the hours parked, t, that would make the cost of each garage the same is 5 hours
Box 1 = 6 & 3/8 kilograms.
Box 2 = 7 & 2/8 kilograms.
6 & 3/8 + 7 &2/8 = 13 & 5/8 kilograms.
Therefore the combined weight of the boxes are 13 & 5/8 kilograms.
Answer:
you have to round up so it would round up to 35.800
Step-by-step explanation:
Answer:
If you want to know what the probability is to get at least one Heads, then that is the same as the probability of all the events (100%, or 1) minus the probability of getting all Tails.
There are 100 coins. 99 are fair, 1 is biased with both sides as heads. With a fair coin, the probability of three heads is 0.53=1/8. The probability of picking the biased coin: P(biased coin)=1/100.
Step-by-step explanation:
Answer:
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Step-by-step explanation:
