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2 years ago

14

The area of a figure is 13 square inches. If all the dimensions of the figure are multiplied by 4, the area of the figure will b

e multiplied by _____. 2 4 8 16

1 answer:

salantis [7]2 years ago

4 0

Answer:

option D.

Step-by-step explanation:

Given,

Area of a figure = 13 in²

All dimension is multiplied by 4.

Area of the figure will be multiplied by = ?

We know that,

$Area\ \alpha \ (Length)^2$

If length is multiplied by 4.

$Area\ \alpha \ 4^2 (L)^2$

Where L is the dimension of the figure.

$Area\ \alpha \ 16 (L)^2$

Area of the figure will be multiplied by 16.

Hence, correct answer is option D.

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LekaFEV [45]

Answer:

A≈254.47ft²

Step-by-step explanation:

A=πr2=π·92≈254.469ft²

7 0

2 years ago

The mean of a set of data is 148.87 and its standard deviation is 68.29. Find the z score for a value of 490.19.

Ksivusya [100]

<span>The mean of a set of data is 148.87 and its standard deviation is 68.29. Find the z score for a value of 490.19
the z-score is given by:
z=(x-</span>μ<span>)/</span>σ
plugging in the values in the expression we get:
z=(490.19-149.87)/68.29
z=340.32/68.29
z=4.9835

6 0

3 years ago

Which expressions are equivalent to the one below? Check all that apply. log2 16 + log2 16 A. log2(28) B. 8 C. log 256 D. log2 2

eduard

Answer:

B. 8.

D. log2 256.

Step-by-step explanation:

Generally:

loga b + loga b

= loga b^2.

Therefore log2 16 + log2 16

= log2 16^2

= log2 256.

From the above:

256 = 2^x where x is the log.

Now 2^8 = 256 so the original log2 16 + log2 16 = 8.

3 0

2 years ago

Read 2 more answers

Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140

Westkost [7]

Answer:

The amount each took home was 20 unit currency.

Step-by-step explanation:

We are given that Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140 apples, went to market and sold all their apples at the same price, and each received the same sum of money.

Formula : $a \times n + (n - 1)$ , $(a + b)\cdot n + (n - 2)$ , $(a + 2 \cdot b) \cdot n + (n - 3)$ , $(a + 3 \cdot b) \cdot n + (n - 4)$ , $(a + 4 \cdot b) \cdot n + (n - 5)$ , $(a + 5 \cdot b) \cdot n + (n - 6)$ , $(a + 6 \cdot b) \cdot n + (n - 7)$

$a \cdot n + (n - 1) = 20$

$(a + b) \cdot n + (n - 2)=40$

$(a + 2 \cdot b) \cdot n + (n - 3) = 60$

$(a + 3 \cdot b) \cdot n + (n - 4) = 80$

$(a + 4 \cdot b) \cdot n + (n - 5) = 100$

$(a + 5 \cdot b) \cdot n + (n - 6) = 120$

$(a + 6 \cdot b) \cdot n + (n - 7) = 140$

On solving :

n = 7, a = 2, b = 3

So,

$2 \times 7 + 6 = 20$

$5 \times 7 + 5=40$

$8 \times 7 + 4 = 60$

$11 \times 7 + 3 = 80$

$14 \times 7 + 2 = 100$

$17 \times 7 + 1 = 120$

Based on market pricing if groups of apples are sold at 1 unit currency for 7, and extras are sold for 3 unit currency per extra 1, we have the amount :

2×1 + 6×3 = 20

5×1 + 5×3=20

8×1 + 4×3 = 20

11×1 + 3×3 = 20

14×1 + 2×3 = 20

17×1 + 1×3 = 20

20×1 = 20

Therefore, the amount each took home was 20 unit currency.

4 0

2 years ago

At the end of last year mark odometer reads 74,924 miles.at the end of this year , his odometer. reads 90,405 miles. How many mi

maks197457 [2]

Mark drove 165,329 miles year

6 0

2 years ago