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3 years ago

9

Wholelotta swag aneways

1 answer:

aksik [14]3 years ago

3 0

Answer:

period.

Step-by-step explanation:

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Taylor surveys students in one grade level who own at least one pet. She finds that 50% of the students surveyed own 2 pets, 3 s

Llana [10]

First, we need to work out the total number of students who were being surveyed.

We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population

That means total number of students being surveyed is 13+13=26 students

Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13

The probability distribution is shown in the table below. Let $x$ be the number of pets and $P(X=x)$ is the probability of owning the number of pets

3 0

4 years ago

Read 2 more answers

A soda company produces 12 oz cans of soda. The mean volume is 12 oz with a

Lena [83]

Answer:

456

Step-by-step explanation:

11.5 oz would be 2 standard deviations below the mean... z -score = -2 = .0228 (from Z-Score table)

22.8% of 2000 = 456

7 0

2 years ago

A general contractor is constructing a building that requires a concrete foundation that is to be 20 feet by 12 feet and 4 inche

ikadub [295]

First we calculate the volume of the foundation:

Volume (V) = 20 ft * 12 ft * 4 in (1 ft / 12 in)

V = 80 ft^3

Since the cost is in cubic yard (yard^3) so convert:

V = 80 ft^3 * (1 yard^3 / 27 ft^3) = 2.963 yard^3

So the total cost is:

cost = ($125 / yard^3) * 2.963 yard^3

<span>cost = $370.37</span>

7 0

4 years ago

Read 2 more answers

Solve each system of linear equations by elimination. <br><br>2v=-5 +10 <br>-15=-3x + 5y

Burka [1]

Answer:Just solve it. This is Algebra. Not that hard. Use Substation Method

Step-by-step explanation:

3 0

3 years ago

(Small sample confidence intervals for a population mean) suppose you are taking a sampling of 15 measurements. you find that x=

Luda [366]

Answer:

The 99% confidence interval is $71.67 < \mu < 78.33$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 15$

The sample mean is $\= x = 75$

The standard deviation is $s = 5$

Given that confidence is 99% then the level of significance is mathematically represented as

$\alpha = 100 - 99$

$\alpha = 1\%$

$\alpha = 0.01$

Next we obtain the critical values of $\frac{ \alpha }{2}$ from the normal distribution table

The value is

$Z_{\frac{ \alpha }{2} } = 2.58$

Generally the margin for error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ s}{ \sqrt{n} }$

=> $E = 2.58 * \frac{ 5}{ \sqrt{15} }$

=> $E = 3.3307$

The 99% confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

=> $75 - 3.3307 < \mu$

=> $71.67 < \mu < 78.33$

3 0

3 years ago