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TEA [102]
3 years ago
13

Write a statement relating the opposites of each of the given numbers.

Mathematics
2 answers:
Leokris [45]3 years ago
8 0
Yes -1/5 is less than 1/3
Lesechka [4]3 years ago
3 0
-1/5 is less than 1/3 because it’s a negative.

The opposite of -1/5 is 1/5 and 1/3 is -1/3.
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Part A: You have $0.80 in your backpack in dimes and quarters. Let x represent the number of dimes and y represent the number of
Alik [6]
Part A: 0.10x + 0.25 = 0.80 (dimes are 10 cents or 0.10 dollars, quarters are 0.25 dollars)
Part B: Plug in what you DO know and solve the one you DON’T:
0.10x + 0.25(2) = 0.80
0.10x + 0.50 = 0.80. Subtract 0.50 from both sides:
0.10x = 0.30 (Divide both sides by 0.10)
x = 3
Therefore you have 3 dimes
8 0
3 years ago
1 find the area in square cm of a square whose side is
lara [203]
For question 1:

Part i)

2.6 x 2.6 = 6.76 cm squared

No unit conversions needed

Part ii)

1.2 dm = 1.2 / 1000000 = 0.0000012 cm

0.0000012 x 0.0000012 = 0.00000000000144 cm squared

Question 2:

16.5dm = 16.5/ 1000 = 0.0165 m

0.0165 x 0.0165 = 0.00027225 m squared

I hope this has helped
3 0
3 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
This question has three parts. Answer the parts in order.
Whitepunk [10]

Answer:

b

Step-by-step explanation:

b

5 0
3 years ago
Given a≠±b and a^2−b^2 / a+b =12, find a−b.<br> pls hlep
Readme [11.4K]

Answer:

a - b = 12

Step-by-step explanation:

Given

\frac{a^2-b^2}{a+b} = 12 ← factor the numerator

a² - b² ← is a difference of squares and factors as

a² - b² = (a - b)(a + b)

Thus

\frac{(a-b)(a+b)}{a+b} = 12

Cancel the common factor (a + b) on numerator/ denominator, thus

a - b = 12

7 0
3 years ago
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