Answer:
The answer is 7.
Step-by-step explanation:
I have used an Online Algebra calculator to check my answer with so this answer is 100% correct.
PLEASE MARK BRAINLIEST.(THE CROWN ON THE LOWER RIGHT- HAND SIDE OF ANSWER.)
EXPLANATION:
Given;
We are given that in a class there are the following groups of students;

Required;
We are required to calculate the probability that a student selected at random will have Green eyes OR Blue eyes.
Step-by-step solution;
To calculate the probability of an event, we shall use the following formula;
![P[Event]=\frac{Number\text{ }of\text{ }required\text{ }outcomes}{Number\text{ }of\text{ }all\text{ }possible\text{ }outcomes}](https://tex.z-dn.net/?f=P%5BEvent%5D%3D%5Cfrac%7BNumber%5Ctext%7B%20%7Dof%5Ctext%7B%20%7Drequired%5Ctext%7B%20%7Doutcomes%7D%7BNumber%5Ctext%7B%20%7Dof%5Ctext%7B%20%7Dall%5Ctext%7B%20%7Dpossible%5Ctext%7B%20%7Doutcomes%7D)
To calculate the probability that a selected student will have green eyes;
![P[green]=\frac{6}{20}=\frac{3}{10}](https://tex.z-dn.net/?f=P%5Bgreen%5D%3D%5Cfrac%7B6%7D%7B20%7D%3D%5Cfrac%7B3%7D%7B10%7D)
To calculate the probability that a selected student will have blue eyes;
![P[blue]=\frac{5}{20}=\frac{1}{4}](https://tex.z-dn.net/?f=P%5Bblue%5D%3D%5Cfrac%7B5%7D%7B20%7D%3D%5Cfrac%7B1%7D%7B4%7D)
The probability of event A or event B will be the addition of probabilities.
Therefore, the probability that a randomly selected student will have green or blue eyes will be;
![P[G]+P[B]=\frac{3}{10}+\frac{1}{4}](https://tex.z-dn.net/?f=P%5BG%5D%2BP%5BB%5D%3D%5Cfrac%7B3%7D%7B10%7D%2B%5Cfrac%7B1%7D%7B4%7D)
![P[F]+P[B]=\frac{6}{20}+\frac{5}{20}=\frac{11}{20}](https://tex.z-dn.net/?f=P%5BF%5D%2BP%5BB%5D%3D%5Cfrac%7B6%7D%7B20%7D%2B%5Cfrac%7B5%7D%7B20%7D%3D%5Cfrac%7B11%7D%7B20%7D)
Therefore,
ANSWER:
Answer:
2x-18
Step-by-step explanation:
2(x-9)
distribute the 2 in the ( )
2x-18
Hope this Helps!!!
Answer:
ok
Step-by-step explanation:
Answer:
y=1
Step-by-step explanation:
y = 11x + 1
11x + 12y = 12
Take the right side of the first equation, which is 11x + 1,
since y equals it, put it in parentheses like this (11x + 1)
and put it in place of y in the second equation.
The second equation is
11x + 12y = 12
Take out the y and put in (11x + 1) in place of the y:
11x + 12(11x + 1) = 12
Remove the parentheses by using the distributive principle:
11x + 132x + 12 = 12
Combine like terms on the left
143x + 12 = 12
Subtract 12 from both sides
143x = 0
Divide both sides by 143
x = 0
Now go back and get the very first equation:
y = 11x + 1
And substitute (0) for x:
y = 11(0) + 1
y = 0 + 1
y = 1