Question

In a genetics class, 6 students have GREEN eyes, 5 students have BLUE eyes, and 9 have HAZEL eyes. If a single student is picked at random, what is the probability that their eyes are GREEN or BLUE?Provide the final answer as a simplified fraction.Provide your answer below:

Answer 1

EXPLANATION:

Given;

We are given that in a class there are the following groups of students;

$\begin{gathered} Green\text{ }eyes=6 \\ Blue\text{ }eyes=5 \\ Hazel\text{ }eyes=9 \end{gathered}$

Required;

We are required to calculate the probability that a student selected at random will have Green eyes OR Blue eyes.

Step-by-step solution;

To calculate the probability of an event, we shall use the following formula;

$P[Event]=\frac{Number\text{ }of\text{ }required\text{ }outcomes}{Number\text{ }of\text{ }all\text{ }possible\text{ }outcomes}$

To calculate the probability that a selected student will have green eyes;

$P[green]=\frac{6}{20}=\frac{3}{10}$

To calculate the probability that a selected student will have blue eyes;

$P[blue]=\frac{5}{20}=\frac{1}{4}$

The probability of event A or event B will be the addition of probabilities.

Therefore, the probability that a randomly selected student will have green or blue eyes will be;

$P[G]+P[B]=\frac{3}{10}+\frac{1}{4}$$P[F]+P[B]=\frac{6}{20}+\frac{5}{20}=\frac{11}{20}$

Therefore,

ANSWER:

$P[G\text{ }orB]=\frac{11}{20}$